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ICPC-2018 徐州网络赛G题(STL-set, 二分, 思维)

题目链接

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#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <vector>
#include <set>
using namespace std;
typedef long long ll;

int n;

ll solve(vector<int> vec) {
int sz = vec.size();
set<int> st;
ll ans = 0;
for(int i = sz-1; i >= 0; i--) {
set<int>::iterator it = st.lower_bound(vec[i]);
if(it == st.begin()) {
ans += vec[i];
} else {
it--;
ans += vec[i] - *it;
}
st.insert(vec[i]);
}
return ans;
}

int main() {
while(scanf("%d", &n) != EOF) {
vector<int> vec1, vec2;
int x, y;
for(int i = 1; i <= n; i++) {
scanf("%d%d", &x, &y);
vec1.push_back(x);
vec2.push_back(y);
}
cout << solve(vec1) + solve(vec2) << endl;
}

return 0;
}

树状数组写法之后再补

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