0%

SCOI2005互不侵犯 (状压DP)

题目链接

参考博客

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
//2021-08-19 16:24:46
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 2010;

int sta[N], tot_line[N];
int cnt = 0;
int n, king;
ll f[10][N][110];

void dfs(int status, int sum, int pos) {
if(pos >= n) {
sta[++cnt] = status;
tot_line[cnt] = sum;
return;
}
dfs(status, sum, pos + 1);
dfs(status+(1<<pos), sum+1, pos+2);
}


int main() {
scanf("%d%d", &n, &king);
dfs(0, 0, 0);
for(int i = 1; i <= cnt; i++) {
f[1][i][tot_line[i]] = 1;
}
for(int i = 2; i <= n; i++) {
for(int j = 1; j <= cnt; j++) {
for(int k = 1; k <= cnt; k++) {
if(sta[j] & sta[k]) continue;
if((sta[j]<<1) & sta[k]) continue;
if(sta[j] & (sta[k]<<1)) continue;
for(int s = king; s >= tot_line[j]; s--) {
f[i][j][s] += f[i-1][k][s-tot_line[j]];
}
}
}
}
ll ans = 0;
for(int i = 1; i <= cnt; i++) {
ans += f[n][i][king];
}
printf("%lld\n", ans);

return 0;
}
求大佬赏个饭